The reverse of steam reforming is an exothemic process
CO(g) + 3H2(g)
CH4(g) + H2O(g)
ΔrH = 206 kJ mol−1
The equilibrium constant, Kp, for this reaction, at 25 oC
is (8.6 × 10−26)−1 = 1.6 × 1025, far to the right.
At 325 oC, Kp = 5 × 106, smaller but still well to the right.
this is made use of to remove traces of carbon monoxide, CO,
from the gas stream of hydrogen, H2 used with nitrogen, N2
in the Haber process to make ammonia.