Section 15, Answer 1

Couple	Half-reaction	E / V
Zn²⁺/Zn	Zn²⁺ + 2e¯ Zn	−0.76
Sn²⁺/Sn	Sn²⁺ + 2e¯ Sn	−0.14
Cu²⁺/Cu	Cu²⁺ + 2e¯ Cu	0.34
I₂/I¯	I₂ + 2e¯ 2I¯	0.54
Fe³⁺/Fe²⁺	Fe³⁺ + e¯ Fe²⁺	0.77
Ag⁺/Ag	Ag⁺ + e¯ Ag	0.80
Br₂/Br¯	Br₂ + 2e¯ 2Br¯	1.10
O₂/H₂O	O₂ + 4H⁺ + 4e¯ 2H₂O	1.23
Cl₂/Cl¯	Cl₂ + 2e¯ 2Cl¯	1.40

As the Ag⁺/Ag couple is negative with respect to the Cl₂/Cl¯ couple the cell will be
Ag|Ag⁺||Cl₂,Cl¯|Pt
and silver will reduce chlorine in this reaction.

Thus the half reactions and the cell reaction will be:
AgAg⁺ + e¯
Cl₂ + 2e¯2Cl¯
2Ag + Cl₂2Ag⁺ + 2Cl¯

and the cell potential, E = E(Cl₂/Cl¯) − E(Ag⁺) = 1.40 V − 0.80 V = 0.60 V