Zn Sn2+ + 2e¯ Sn
Cu I2 + 2e¯ 2I¯
Fe2+ Ag 2Br¯ 2H2O 2Cl¯| Couple | Half-reaction | E / V
| Zn2+/Zn |
Zn2+ + 2e¯ |
Zn−0.76 |
Sn2+/Sn |
|
Sn2+ + 2e¯ −0.14 |
Cu2+/Cu |
Cu2+ + 2e¯ |
Cu0.34 |
I2/I¯ |
|
I2 + 2e¯ 0.54 |
Fe3+/Fe2+ |
Fe3+ + e¯ |
Fe2+0.77 |
Ag+/Ag |
Ag+ + e¯ |
Ag0.80 |
Br2/Br¯ |
Br2 + 2e¯ |
2Br¯1.10 |
O2/H2O |
O2 + 4H+ + 4e¯ |
2H2O1.23 |
Cl2/Cl¯ |
Cl2 + 2e¯ |
2Cl¯1.40 |
|
|---|
|
Yes, because Sn, the reductant, is above Br2, the oxidant, in the table.
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